What is the inverse of f(x)=sqrt(x^2-10x) ?

The inverse of f(x)=sqrt(x^2-10x) is 5+sqrt(x^2+25),5-sqrt(x^2+25)

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inverse of f(x)=sqrt(x^2-10x)

inverse

f (x) = x^{2} - 10 x

5 + x^{2} + 25, 5 - x^{2} + 25

Solution steps

y = x^{2} - 10 x

Replace

x

with

y

x = y^{2} - 10 y

Solve for

y, x = y^{2} - 10 y

5 + x^{2} + 25, 5 - x^{2} + 25

f (x) = 3 x^{2} + 10 x - 2

\frac{x}{( x + 3 )} \circ \frac{6}{x}

f (x) = \frac{( x - 3 ) ^{7} + 1}{7}

3 x^{4} - 18 x^{2}

What is the inverse of f(x)=sqrt(x^2-10x) ?
The inverse of f(x)=sqrt(x^2-10x) is 5+sqrt(x^2+25),5-sqrt(x^2+25)