What is the domain of x/((x+3))\circ 6/x ?

The domain of x/((x+3))\circ 6/x is x 0

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domain of x/((x+3))\circ 6/x

domain

\frac{x}{( x + 3 )} \circ \frac{6}{x}

x < - 3 or - 3 < x < 0 or x > 0

Solution steps

Find undefined (singularity) points:

x = - 3, x = 0

The function domain

x < - 3 or - 3 < x < 0 or x > 0

f (x) = \frac{( x - 3 ) ^{7} + 1}{7}

3 x^{4} - 18 x^{2}

f (x) = \frac{x + 4}{x ^{2}}

f (x) = x + 18

What is the domain of x/((x+3))\circ 6/x ?
The domain of x/((x+3))\circ 6/x is x<-3\lor-3<x<0\lor x>0