What is the inverse of f(x)=x^2-8x+4 ?

The inverse of f(x)=x^2-8x+4 is 4+sqrt(x+12),4-sqrt(x+12)

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inverse of f(x)=x^2-8x+4

inverse

f (x) = x^{2} - 8 x + 4

4 + x + 12, 4 - x + 12

Solution steps

y = x^{2} - 8 x + 4

Replace

x

with

y

x = y^{2} - 8 y + 4

Solve for

y, x = y^{2} - 8 y + 4

4 + x + 12, 4 - x + 12

f (x) = (9 - x^{2}) (x + 1)

(- 8, - 3), (2, 3)

f (x) = \frac{14}{1 + 3 ^{- x}}

f (x) = \frac{1}{3} x + 7

\frac{1}{x + 6} + 5

What is the inverse of f(x)=x^2-8x+4 ?
The inverse of f(x)=x^2-8x+4 is 4+sqrt(x+12),4-sqrt(x+12)