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midpoint
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asymptotes of f(x)=(14)/(1+3^{-x)}inverse of f(x)= 1/3 x+7range of 1/(x+6)+5perpendicular-4x-5y=7,(-4,-3)inverse of x^5-2
Frequently Asked Questions (FAQ)
What is the midpoint (-8,-3),(2,3) ?
The midpoint (-8,-3),(2,3) is (-3,0)