What is the critical x/(x^2+15x+54) ?

The critical x/(x^2+15x+54) is x=-3sqrt(6),x=3sqrt(6)

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critical x/(x^2+15x+54)

critical points

\frac{x}{x ^{2} + 15 x + 54}

x = - 36, x = 36

Solution steps

\frac{x}{x ^{2} + 15 x + 54}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 36, x = 36, x = - 9, x = - 6

Identify critical points not in

f (x)

domain

Domain of

\frac{x}{x ^{2} + 15 x + 54} : x < - 9 or - 9 < x < - 6 or x > - 6

\frac{x}{x ^{2} + 15 x + 54}

is not defined at

x = - 9, x = - 6

, therefore:

x = - 36, x = 36

(- 6.2) (- 6.6)

f (x) = 5 x - 1

f (x) = - x^{3} + 9 x^{2} - 8 x - 4

(x - 3)^{\frac{2}{3}}

4 sin (\frac{6}{7} x) + 5

What is the critical x/(x^2+15x+54) ?
The critical x/(x^2+15x+54) is x=-3sqrt(6),x=3sqrt(6)