What is the critical (x-3)^{2/3} ?

The critical (x-3)^{2/3} is x=3

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critical (x-3)^{2/3}

critical points

(x - 3)^{\frac{2}{3}}

x = 3

Solution steps

(x - 3)^{\frac{2}{3}}

Find where

f^{'} (x)

is equal to zero or undefined

x = 3

Identify critical points not in

f (x)

domain

Domain of

(x - 3)^{\frac{2}{3}} : - \infty < x < \infty

All critical points are in domain

x = 3

4 sin (\frac{6}{7} x) + 5

f (x) = \frac{5}{x}

f (x) = 3 x - x^{2}

f (x) = lo g_{6} (x - 2)

\frac{3}{x ^{2} - 16}