en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

distance (-2,4),(4,0)

Solution

distance

(- 2, 4), (4, 0)

Solution

213

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(- 2, 4)

and

(4, 0)

is

= (4 - (- 2))^{2} + (0 - 4)^{2}

Simplify

= 213

Popular Examples

monotone f(x)=x^2sqrt(1-x)monotone intervals

f (x) = x^{2} 1 - x

intercepts of f(x)=x^2+y^2=4 intercepts

f (x) = x^{2} + y^{2} = 4

critical 2sin^2(x)critical points

2 sin^{2} (x)

domain of f(x)= 3/(x^2+9)+7/(x^2-25)domain

f (x) = \frac{3}{x ^{2} + 9} + \frac{7}{x ^{2} - 25}

intercepts of f(x)=(x^2+9x+20)/(4x+16)intercepts

f (x) = \frac{x ^{2} + 9 x + 20}{4 x + 16}

Frequently Asked Questions (FAQ)

What is the distance (-2,4),(4,0) ?
The distance (-2,4),(4,0) is 2sqrt(13)