What is the critical 2sin^2(x) ?

The critical 2sin^2(x) is x=pin,x= pi/2+pin

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critical 2sin^2(x)

critical points

2 sin^{2} (x)

x = πn, x = \frac{π}{2} + πn

Solution steps

2 sin^{2} (x)

Find where

f^{'} (x)

is equal to zero or undefined

x = πn, x = \frac{π}{2} + πn

Identify critical points not in

f (x)

domain

Domain of

2 sin^{2} (x) : - \infty < x < \infty

All critical points are in domain

x = πn, x = \frac{π}{2} + πn

f (x) = \frac{3}{x ^{2} + 9} + \frac{7}{x ^{2} - 25}

f (x) = \frac{x ^{2} + 9 x + 20}{4 x + 16}

x^{3} + x

f (x) = 5 x

f (x) = (x - 3)^{2}