What is the extreme f(x)=x^3+3x^2-9x-5 ?

The extreme f(x)=x^3+3x^2-9x-5 is Maximum(-3,22),Minimum(1,-10)

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extreme f(x)=x^3+3x^2-9x-5

extreme points

f (x) = x^{3} + 3 x^{2} - 9 x - 5

Maximum (- 3, 22), Minimum (1, - 10)

Solution steps

f^{'} (x) = 3 x^{2} + 6 x - 9

Find intervals:

Increasing

: - \infty < x < - 3,

Decreasing

: - 3 < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - 3

into

x^{3} + 3 x^{2} - 9 x - 5 : 22

Maximum (- 3, 22)

Plug

x = 1

into

x^{3} + 3 x^{2} - 9 x - 5 : - 10

Minimum (1, - 10)

Maximum (- 3, 22), Minimum (1, - 10)

f (x) = x^{2} - 12 x + 4

n^{3} + 2

2 x^{2} + 2

5 x^{2} ln (\frac{x}{4})

(3, - 9), (6, - 2)

What is the extreme f(x)=x^3+3x^2-9x-5 ?
The extreme f(x)=x^3+3x^2-9x-5 is Maximum(-3,22),Minimum(1,-10)