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Popular >

extreme 5x^2ln(x/4)

Solution

extreme points

5 x^{2} ln (\frac{x}{4})

Solution

Minimum (\frac{4}{e}, - \frac{40}{e})

Solution steps

f^{'} (x) = 5 (2 x ln (\frac{x}{4}) + x)

Find intervals:

Decreasing

: 0 < x < \frac{4}{e},

Increasing

: \frac{4}{e} < x < \infty

Plug

x = \frac{4}{e}

into

5 x^{2} ln (\frac{x}{4}) : - \frac{40}{e}

Minimum (\frac{4}{e}, - \frac{40}{e})

Popular Examples

distance (3,-9),(6,-2)distance

(3, - 9), (6, - 2)

midpoint (7,-2),(-4,2)midpoint

(7, - 2), (- 4, 2)

inverse of sqrt(x+2)-3 inverse

x + 2 - 3

extreme f(x)=2x^2+8x-5 extreme points

f (x) = 2 x^{2} + 8 x - 5

range of f(x)=2(1/2)^x range

f (x) = 2 (\frac{1}{2})^{x}

Frequently Asked Questions (FAQ)

What is the extreme 5x^2ln(x/4) ?
The extreme 5x^2ln(x/4) is Minimum(4/(sqrt(e)),-(40)/e)