What is the inverse of f(x)=4x^2+8x+13 ?

The inverse of f(x)=4x^2+8x+13 is (-2+sqrt(x-9))/2 ,-(sqrt(x-9)+2)/2

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inverse of f(x)=4x^2+8x+13

inverse

f (x) = 4 x^{2} + 8 x + 13

\frac{- 2 + x - 9}{2}, - \frac{x - 9 + 2}{2}

Solution steps

y = 4 x^{2} + 8 x + 13

Replace

x

with

y

x = 4 y^{2} + 8 y + 13

Solve for

y, x = 4 y^{2} + 8 y + 13

\frac{- 2 + x - 9}{2}, - \frac{x - 9 + 2}{2}

f (x) = \frac{x ^{3} + 27}{x + 3}

f (x) = (- \frac{16}{( 3 + t ) ^{2}})

\frac{x - 2}{x ^{2} + 5 x + 4}

f (x) = 2 x - 1

(- 4, 2), (4, 2)

What is the inverse of f(x)=4x^2+8x+13 ?
The inverse of f(x)=4x^2+8x+13 is (-2+sqrt(x-9))/2 ,-(sqrt(x-9)+2)/2