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Popular >

distance (-4,2),(4,2)

Solution

distance

(- 4, 2), (4, 2)

Solution

8

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(- 4, 2)

and

(4, 2)

is

= (4 - (- 4))^{2} + (2 - 2)^{2}

Simplify

= 8

Popular Examples

inverse of f(x)=-(x^2)inverse

f (x) = - (x^{2})

parity f(x)=-x^3+8 parity

f (x) = - x^{3} + 8

domain of f(x)=x^3+4x+3 domain

f (x) = x^{3} + 4 x + 3

critical f(x)=(x^2)/(x^2-16)critical points

f (x) = \frac{x ^{2}}{x ^{2} - 16}

domain of f(x)=(x+2)/x domain

f (x) = \frac{x + 2}{x}

Frequently Asked Questions (FAQ)

What is the distance (-4,2),(4,2) ?
The distance (-4,2),(4,2) is 8