What is the intercepts of f(x)=(x^2-2x)/(2x^2-32) ?

The intercepts of f(x)=(x^2-2x)/(2x^2-32) is X Intercepts: (2,0),(0,0),Y Intercepts: (0,0)

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intercepts of f(x)=(x^2-2x)/(2x^2-32)

intercepts

f (x) = \frac{x ^{2} - 2 x}{2 x ^{2} - 32}

X Intercepts : (2, 0), (0, 0), Y Intercepts : (0, 0)

Solution steps

x -

axis interception points of

\frac{x ^{2} - 2 x}{2 x ^{2} - 32} : (2, 0), (0, 0)

y -

axis interception point of

\frac{x ^{2} - 2 x}{2 x ^{2} - 32} : (0, 0)

X Intercepts : (2, 0), (0, 0), Y Intercepts : (0, 0)

6 x - 5 y = 3

f (x) = 4 x^{2} + 8 x + 13

f (x) = \frac{x ^{3} + 27}{x + 3}

f (x) = (- \frac{16}{( 3 + t ) ^{2}})

\frac{x - 2}{x ^{2} + 5 x + 4}

What is the intercepts of f(x)=(x^2-2x)/(2x^2-32) ?
The intercepts of f(x)=(x^2-2x)/(2x^2-32) is X Intercepts: (2,0),(0,0),Y Intercepts: (0,0)