What is the inverse of f(x)=7(\sqrt[3]{x}-6) ?

The inverse of f(x)=7(\sqrt[3]{x}-6) is (x^3}{343}+(18x^2)/(49)+\frac{108x)/7+216

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inverse of f(x)=7(\sqrt[3]{x}-6)

inverse

\frac{x ^{3}}{343} + \frac{18 x ^{2}}{49} + \frac{108 x}{7} + 216

Solution steps

Replace

x

with

y

Solve for

\frac{x ^{3}}{343} + \frac{18 x ^{2}}{49} + \frac{108 x}{7} + 216

f (x) = - \frac{3}{2 t ^{\frac{3}{2}}}

f (x) = 5 sin (\frac{1}{2} x)

\frac{1}{10} (x + 6)^{2} + 4

f (x) = x^{2} + 6 x + 3

y = - 4

What is the inverse of f(x)=7(\sqrt[3]{x}-6) ?
The inverse of f(x)=7(\sqrt[3]{x}-6) is (x^3}{343}+(18x^2)/(49)+\frac{108x)/7+216