What is the inverse of f(x)=7(\sqrt[3]{x}-6) ?

The inverse of f(x)=7(\sqrt[3]{x}-6) is (x^3}{343}+(18x^2)/(49)+\frac{108x)/7+216

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inverse of f(x)=7(\sqrt[3]{x}-6)

inverse

\frac{x ^{3}}{343} + \frac{18 x ^{2}}{49} + \frac{108 x}{7} + 216

Solution steps

y = 7 (3 x - 6)

Replace

x

with

y

x = 7 (3 y - 6)

Solve for

y, x = 7 (3 y - 6)

\frac{x ^{3}}{343} + \frac{18 x ^{2}}{49} + \frac{108 x}{7} + 216

What is the inverse of f(x)=7(\sqrt[3]{x}-6) ?
The inverse of f(x)=7(\sqrt[3]{x}-6) is (x^3}{343}+(18x^2)/(49)+\frac{108x)/7+216