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Popular >

range of 1/10 (x+6)^2+4

Solution

range

\frac{1}{10} (x + 6)^{2} + 4

Solution

f (x) \geq 4

+1

Solution steps

Vertex of

\frac{1}{10} (x + 6)^{2} + 4 :

Minimum

(- 6, 4)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = \frac{1}{10},

Vertex

(x_{v}, y_{v}) = (- 6, 4)

f (x) \geq 4

Popular Examples

extreme f(x)=x^2+6x+3 extreme points

f (x) = x^{2} + 6 x + 3

inverse of y=-4 inverse

y = - 4

inverse of f(x)=\sqrt[3]{x+8}-6 inverse

domain of f(x)=sqrt(2t+6)domain

f (x) = 2 t + 6

inverse of e^{x-2}inverse

e^{x - 2}

Frequently Asked Questions (FAQ)

What is the range of 1/10 (x+6)^2+4 ?
The range of 1/10 (x+6)^2+4 is f(x)>= 4