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Beliebt Funktionen >

extreme f(x)=110.2x-0.4x^2-20.2-2000

Lösung

extrempunkte

f (x) = 110.2 x - 0.4 x^{2} - 20.2 - 2000

Lösung

Maximum (\frac{551}{4}, 5569.825)

Schritte zur Lösung

f^{'} (x) = - 0.8 x + 110.2

Intervalle finden:

Ansteigend

: - \infty < x < \frac{551}{4},

Absteigend

: \frac{551}{4} < x < \infty

Stecke

x = \frac{551}{4}

in

110.2 x - 0.4 x^{2} - 20.2 - 2000 : 5569.825

Maximum (\frac{551}{4}, 5569.825)

Graph

Beliebte Beispiele

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e x t re m e f (x) = \frac{x ^{3}}{3} - 16 x^{2} + 240 x - 36

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