What is the extreme f(x)=((x))/((6x+2)),5<= x<= 8 ?

The extreme f(x)=((x))/((6x+2)),5<= x<= 8 is Minimum(5, 5/32),Maximum(8, 4/25)

extreme f(x)=((x))/((6x+2)),5<= x<= 8

extreme points

f (x) = \frac{( x )}{( 6 x + 2 )}, 5 \leq x \leq 8

Minimum (5, \frac{5}{32}), Maximum (8, \frac{4}{25})

Solution steps

Find the critical points:

x = 5, x = 8

Domain of

\frac{x}{6 x + 2}, 5 \leq x \leq 8 : 5 \leq x \leq 8

Find intervals:

Increasing

: 5 < x < 8

Plug the extreme point

x = 5

into

\frac{x}{6 x + 2} \Rightarrow y = \frac{5}{32}

Minimum (5, \frac{5}{32})

Plug the extreme point

x = 8

into

\frac{x}{6 x + 2} \Rightarrow y = \frac{4}{25}

Maximum (8, \frac{4}{25})

Minimum (5, \frac{5}{32}), Maximum (8, \frac{4}{25})

f (x, y) = (x - 1)^{3} + (x - 1)^{2} + (y + 1)^{2}

f (x, y) = x^{2} - 2 y^{2} - x + y

f (x) = x^{4} - 18 x^{2} + 1, - 6 \leq x \leq 6

f (x) = 3 x^{5} - 25 x^{3} + 60 x

x^{2} + x y + y^{2} - 7 x - 3 y

What is the extreme f(x)=((x))/((6x+2)),5<= x<= 8 ?
The extreme f(x)=((x))/((6x+2)),5<= x<= 8 is Minimum(5, 5/32),Maximum(8, 4/25)