What is the extreme x^2+xy+y^2-7x-3y ?

The extreme x^2+xy+y^2-7x-3y is Minimum(11/3 ,-1/3)

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extreme x^2+xy+y^2-7x-3y

extreme points

x^{2} + x y + y^{2} - 7 x - 3 y

Minimum (\frac{11}{3}, - \frac{1}{3})

Solution steps

Find the critical points:

(\frac{11}{3}, - \frac{1}{3})

\frac{\partial ^{2} f}{\partial x ^{2}} = 2

D (x, y) = 3

Check the sign of at each critical point

Check critical point

(\frac{11}{3}, - \frac{1}{3}) :

Minimum

Minimum (\frac{11}{3}, - \frac{1}{3})

10 x^{\frac{1}{2}} - x [100]

f (x) = 2 x^{3} - 2 x^{2} - 2 x + 6

f (x) = (4 x^{2} - 64)^{\frac{1}{5}}

f (x, y) = e^{y^{2} + x^{3} - 6 x y - 6 x + 2 y}

\frac{2 x + 4}{x ^{2} - 16}

What is the extreme x^2+xy+y^2-7x-3y ?
The extreme x^2+xy+y^2-7x-3y is Minimum(11/3 ,-1/3)