What is the extreme f(x)=2x^3-3x^2-252x ?

The extreme f(x)=2x^3-3x^2-252x is Maximum(-6,972),Minimum(7,-1225)

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extreme f(x)=2x^3-3x^2-252x

extreme

Maximum (- 6, 972), Minimum (7, - 1225)

Solution steps

f^{'} (x) = 6 x^{2} - 6 x - 252

Find intervals:

Increasing

: - \infty < x < - 6,

Decreasing

: - 6 < x < 7,

Increasing

: 7 < x < \infty

Plug

x = - 6

into

2 x^{3} - 3 x^{2} - 252 x : 972

Maximum (- 6, 972)

Plug

x = 7

into

2 x^{3} - 3 x^{2} - 252 x : - 1225

Minimum (7, - 1225)

Maximum (- 6, 972), Minimum (7, - 1225)

What is the extreme f(x)=2x^3-3x^2-252x ?
The extreme f(x)=2x^3-3x^2-252x is Maximum(-6,972),Minimum(7,-1225)