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midpoint
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distance (-2,1),(3,-1)distance range of (8x)/(x^2+25)range extreme-5x^3+15x+4extreme points domain of f(x)=sqrt(x+5)-(sqrt(4-x))/xdomain line (-1/2 ,0),(0, 1/4)line
Frequently Asked Questions (FAQ)
What is the midpoint (-3,-5),(4,4) ?
The midpoint (-3,-5),(4,4) is (1/2 ,-1/2)