en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

distance (-2,1),(3,-1)

Solution

distance

(- 2, 1), (3, - 1)

Solution

29

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(- 2, 1)

and

(3, - 1)

is

= (3 - (- 2))^{2} + (- 1 - 1)^{2}

Simplify

= 29

Popular Examples

range of (8x)/(x^2+25)range

\frac{8 x}{x ^{2} + 25}

extreme-5x^3+15x+4 extreme points

- 5 x^{3} + 15 x + 4

domain of f(x)=sqrt(x+5)-(sqrt(4-x))/x domain

f (x) = x + 5 - \frac{4 - x}{x}

line (-1/2 ,0),(0, 1/4)line

(- \frac{1}{2}, 0), (0, \frac{1}{4})

critical f(x)=12x-3x^2 critical points

f (x) = 12 x - 3 x^{2}

Frequently Asked Questions (FAQ)

What is the distance (-2,1),(3,-1) ?
The distance (-2,1),(3,-1) is square root of 29