What is the extreme f(x)=(x-1)(x^2-2x-2) ?

The extreme f(x)=(x-1)(x^2-2x-2) is Maximum(0,2),Minimum(2,-2)

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extreme f(x)=(x-1)(x^2-2x-2)

extreme

Maximum (0, 2), Minimum (2, - 2)

Solution steps

f^{'} (x) = 3 x (- 2 + x)

Find intervals:

Increasing

: - \infty < x < 0,

Decreasing

: 0 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = 0

into

(x - 1) (x^{2} - 2 x - 2) : 2

Maximum (0, 2)

Plug

x = 2

into

(x - 1) (x^{2} - 2 x - 2) : - 2

Minimum (2, - 2)

Maximum (0, 2), Minimum (2, - 2)

What is the extreme f(x)=(x-1)(x^2-2x-2) ?
The extreme f(x)=(x-1)(x^2-2x-2) is Maximum(0,2),Minimum(2,-2)