What is the extreme y=sqrt(1-x^2) ?

The extreme y=sqrt(1-x^2) is Minimum(-1,0),Maximum(0,1),Minimum(1,0)

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extreme y=sqrt(1-x^2)

extreme

Minimum (- 1, 0), Maximum (0, 1), Minimum (1, 0)

Solution steps

f^{'} (x) = - \frac{x}{1 - x ^{2}}

Find intervals:

Increasing

: - 1 < x < 0,

Decreasing

: 0 < x < 1

Plug

x = - 1

into

1 - x^{2} : 0

Minimum (- 1, 0)

Plug

x = 0

into

1 - x^{2} : 1

Maximum (0, 1)

Plug

x = 1

into

1 - x^{2} : 0

Minimum (1, 0)

Minimum (- 1, 0), Maximum (0, 1), Minimum (1, 0)

What is the extreme y=sqrt(1-x^2) ?
The extreme y=sqrt(1-x^2) is Minimum(-1,0),Maximum(0,1),Minimum(1,0)