What is the extreme f(x)=x^2-16x,-4<= x<= 4 ?

The extreme f(x)=x^2-16x,-4<= x<= 4 is Maximum(-4,80),Minimum(4,-48)

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extreme f(x)=x^2-16x,-4<= x<= 4

extreme

Maximum (- 4, 80), Minimum (4, - 48)

Solution steps

Find the critical points:

x = - 4, x = 4

Domain of

x^{2} - 16 x, - 4 \leq x \leq 4 : - 4 \leq x \leq 4

Find intervals:

Decreasing

: - 4 < x < 4

Plug the extreme point

x = - 4

into

x^{2} - 16 x \Rightarrow y = 80

Maximum (- 4, 80)

Plug the extreme point

x = 4

into

x^{2} - 16 x \Rightarrow y = - 48

Minimum (4, - 48)

Maximum (- 4, 80), Minimum (4, - 48)

What is the extreme f(x)=x^2-16x,-4<= x<= 4 ?
The extreme f(x)=x^2-16x,-4<= x<= 4 is Maximum(-4,80),Minimum(4,-48)