What is the extreme h(x)=-6x^3+18x^2+3 ?

The extreme h(x)=-6x^3+18x^2+3 is Minimum(0,3),Maximum(2,27)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

extreme h(x)=-6x^3+18x^2+3

extreme

Minimum (0, 3), Maximum (2, 27)

Solution steps

f^{'} (x) = - 18 x^{2} + 36 x

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < 2,

Decreasing

: 2 < x < \infty

Plug

x = 0

into

- 6 x^{3} + 18 x^{2} + 3 : 3

Minimum (0, 3)

Plug

x = 2

into

- 6 x^{3} + 18 x^{2} + 3 : 27

Maximum (2, 27)

Minimum (0, 3), Maximum (2, 27)

What is the extreme h(x)=-6x^3+18x^2+3 ?
The extreme h(x)=-6x^3+18x^2+3 is Minimum(0,3),Maximum(2,27)