What is the extreme f(x)=x^3-75x+7 ?

The extreme f(x)=x^3-75x+7 is Maximum(-5,257),Minimum(5,-243)

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extreme f(x)=x^3-75x+7

extreme

Maximum (- 5, 257), Minimum (5, - 243)

Solution steps

f^{'} (x) = 3 x^{2} - 75

Find intervals:

Increasing

: - \infty < x < - 5,

Decreasing

: - 5 < x < 5,

Increasing

: 5 < x < \infty

Plug

x = - 5

into

x^{3} - 75 x + 7 : 257

Maximum (- 5, 257)

Plug

x = 5

into

x^{3} - 75 x + 7 : - 243

Minimum (5, - 243)

Maximum (- 5, 257), Minimum (5, - 243)

What is the extreme f(x)=x^3-75x+7 ?
The extreme f(x)=x^3-75x+7 is Maximum(-5,257),Minimum(5,-243)