What is the extreme f(x)=x^3-5x^2-8x+2 ?

The extreme f(x)=x^3-5x^2-8x+2 is Maximum(-2/3 , 130/27),Minimum(4,-46)

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extreme f(x)=x^3-5x^2-8x+2

extreme

Maximum (- \frac{2}{3}, \frac{130}{27}), Minimum (4, - 46)

Solution steps

f^{'} (x) = 3 x^{2} - 10 x - 8

Find intervals:

Increasing

: - \infty < x < - \frac{2}{3},

Decreasing

: - \frac{2}{3} < x < 4,

Increasing

: 4 < x < \infty

Plug

x = - \frac{2}{3}

into

x^{3} - 5 x^{2} - 8 x + 2 : \frac{130}{27}

Maximum (- \frac{2}{3}, \frac{130}{27})

Plug

x = 4

into

x^{3} - 5 x^{2} - 8 x + 2 : - 46

Minimum (4, - 46)

Maximum (- \frac{2}{3}, \frac{130}{27}), Minimum (4, - 46)

What is the extreme f(x)=x^3-5x^2-8x+2 ?
The extreme f(x)=x^3-5x^2-8x+2 is Maximum(-2/3 , 130/27),Minimum(4,-46)