What is the extreme f(x)=-4x^3+12x^2 ?

The extreme f(x)=-4x^3+12x^2 is Minimum(0,0),Maximum(2,16)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

extreme f(x)=-4x^3+12x^2

extreme

Minimum (0, 0), Maximum (2, 16)

Solution steps

f^{'} (x) = - 12 x^{2} + 24 x

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < 2,

Decreasing

: 2 < x < \infty

Plug

x = 0

into

- 4 x^{3} + 12 x^{2} : 0

Minimum (0, 0)

Plug

x = 2

into

- 4 x^{3} + 12 x^{2} : 16

Maximum (2, 16)

Minimum (0, 0), Maximum (2, 16)

What is the extreme f(x)=-4x^3+12x^2 ?
The extreme f(x)=-4x^3+12x^2 is Minimum(0,0),Maximum(2,16)