What is the extreme s(t)=-4.9t^2+29t+2 ?

The extreme s(t)=-4.9t^2+29t+2 is Maximum(145/49 ,44.90816…)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

extreme s(t)=-4.9t^2+29t+2

extreme

Maximum (\frac{145}{49}, 44.90816 \dots)

Solution steps

f^{'} (t) = - 9.8 t + 29

Find intervals:

Increasing

: - \infty < t < \frac{145}{49},

Decreasing

: \frac{145}{49} < t < \infty

Plug

t = \frac{145}{49}

into

- 4.9 t^{2} + 29 t + 2 : 44.90816 \dots

Maximum (\frac{145}{49}, 44.90816 \dots)

What is the extreme s(t)=-4.9t^2+29t+2 ?
The extreme s(t)=-4.9t^2+29t+2 is Maximum(145/49 ,44.90816…)