What is the extreme f(x)=4x^4-2x^3 ?

The extreme f(x)=4x^4-2x^3 is Saddle(0,0),Minimum(3/8 ,-27/1024)

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extreme f(x)=4x^4-2x^3

extreme

Saddle (0, 0), Minimum (\frac{3}{8}, - \frac{27}{1024})

Solution steps

f^{'} (x) = 16 x^{3} - 6 x^{2}

Find intervals:

Decreasing

: - \infty < x < 0,

Decreasing

: 0 < x < \frac{3}{8},

Increasing

: \frac{3}{8} < x < \infty

Plug

x = 0

into

4 x^{4} - 2 x^{3} : 0

Saddle (0, 0)

Plug

x = \frac{3}{8}

into

4 x^{4} - 2 x^{3} : - \frac{27}{1024}

Minimum (\frac{3}{8}, - \frac{27}{1024})

Saddle (0, 0), Minimum (\frac{3}{8}, - \frac{27}{1024})

What is the extreme f(x)=4x^4-2x^3 ?
The extreme f(x)=4x^4-2x^3 is Saddle(0,0),Minimum(3/8 ,-27/1024)