What is the extreme f(x)=x^4-72x^2+3 ?

The extreme f(x)=x^4-72x^2+3 is Minimum(-6,-1293),Maximum(0,3),Minimum(6,-1293)

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extreme f(x)=x^4-72x^2+3

extreme

Minimum (- 6, - 1293), Maximum (0, 3), Minimum (6, - 1293)

Solution steps

f^{'} (x) = 4 x^{3} - 144 x

Find intervals:

Decreasing

: - \infty < x < - 6,

Increasing

: - 6 < x < 0,

Decreasing

: 0 < x < 6,

Increasing

: 6 < x < \infty

Plug

x = - 6

into

x^{4} - 72 x^{2} + 3 : - 1293

Minimum (- 6, - 1293)

Plug

x = 0

into

x^{4} - 72 x^{2} + 3 : 3

Maximum (0, 3)

Plug

x = 6

into

x^{4} - 72 x^{2} + 3 : - 1293

Minimum (6, - 1293)

Minimum (- 6, - 1293), Maximum (0, 3), Minimum (6, - 1293)

What is the extreme f(x)=x^4-72x^2+3 ?
The extreme f(x)=x^4-72x^2+3 is Minimum(-6,-1293),Maximum(0,3),Minimum(6,-1293)