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Popular Functions >

extreme sqrt(x^2+2x+5)

Solution

extreme

Solution

Minimum (- 1, 2)

Solution steps

f^{'} (x) = \frac{x + 1}{x ^{2} + 2 x + 5}

Find intervals:

Decreasing

: - \infty < x < - 1,

Increasing

: - 1 < x < \infty

Plug

x = - 1

into

x^{2} + 2 x + 5 : 2

Minimum (- 1, 2)

Graph

Popular Examples

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extreme (x^2)/(x+2)

extreme f(x,y)=y((1-1)/((x^2+y^2)))

extreme f(x)=2cos(2x)-2,(0,2pi)

Frequently Asked Questions (FAQ)

What is the extreme sqrt(x^2+2x+5) ?
The extreme sqrt(x^2+2x+5) is Minimum(-1,2)