What is the extreme f(x)=|x^2-25| ?

The extreme f(x)=|x^2-25| is Minimum(-5,0),Maximum(0,25),Minimum(5,0)

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extreme f(x)=|x^2-25|

extreme

Minimum (- 5, 0), Maximum (0, 25), Minimum (5, 0)

Solution steps

Find the critical points:

x = - 5, x = 0, x = 5

Find intervals:

Decreasing

: - \infty < x < - 5,

Increasing

: - 5 < x < 0,

Decreasing

: 0 < x < 5,

Increasing

: 5 < x < \infty

Plug the extreme point

x = - 5

into

x^{2} - 25 \Rightarrow y = 0

Minimum (- 5, 0)

Plug the extreme point

x = 0

into

x^{2} - 25 \Rightarrow y = 25

Maximum (0, 25)

Plug the extreme point

x = 5

into

x^{2} - 25 \Rightarrow y = 0

Minimum (5, 0)

Minimum (- 5, 0), Maximum (0, 25), Minimum (5, 0)

What is the extreme f(x)=|x^2-25| ?
The extreme f(x)=|x^2-25| is Minimum(-5,0),Maximum(0,25),Minimum(5,0)