What is the inverse of f(x)=3x^2+4 ?

The inverse of f(x)=3x^2+4 is sqrt((x-4)/3),-sqrt((x-4)/3)

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inverse of f(x)=3x^2+4

inverse

f (x) = 3 x^{2} + 4

\frac{x - 4}{3}, - \frac{x - 4}{3}

Solution steps

y = 3 x^{2} + 4

Replace

x

with

y

x = 3 y^{2} + 4

Solve for

y, x = 3 y^{2} + 4

\frac{x - 4}{3}, - \frac{x - 4}{3}

y = x^{2} - 6 x + 8

x^{2} - 12

\frac{1}{x ^{2} - 3 x + 2}

f (x) = 2 x + 5

y = (2)^{x} - 3

What is the inverse of f(x)=3x^2+4 ?
The inverse of f(x)=3x^2+4 is sqrt((x-4)/3),-sqrt((x-4)/3)