What is the extreme (x-3)/(x^2-18x+81) ?

The extreme (x-3)/(x^2-18x+81) is Minimum(-3,-1/24)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

extreme (x-3)/(x^2-18x+81)

extreme

Minimum (- 3, - \frac{1}{24})

Solution steps

f^{'} (x) = - \frac{x + 3}{( x - 9 ) ^{3}}

Find intervals:

Decreasing

: - \infty < x < - 3,

Increasing

: - 3 < x < 9,

Decreasing

: 9 < x < \infty

Plug

x = - 3

into

\frac{x - 3}{x ^{2} - 18 x + 81} : - \frac{1}{24}

Minimum (- 3, - \frac{1}{24})

What is the extreme (x-3)/(x^2-18x+81) ?
The extreme (x-3)/(x^2-18x+81) is Minimum(-3,-1/24)