What is the extreme-(8*x)/(x^2+1) ?

The extreme-(8*x)/(x^2+1) is Maximum(-1,4),Minimum(1,-4)

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extreme-(8*x)/(x^2+1)

extreme

Maximum (- 1, 4), Minimum (1, - 4)

Solution steps

f^{'} (x) = - \frac{8 ( - x ^{2} + 1 )}{( x ^{2} + 1 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - 1

into

- \frac{8 \cdot x}{x ^{2} + 1} : 4

Maximum (- 1, 4)

Plug

x = 1

into

- \frac{8 \cdot x}{x ^{2} + 1} : - 4

Minimum (1, - 4)

Maximum (- 1, 4), Minimum (1, - 4)

What is the extreme-(8*x)/(x^2+1) ?
The extreme-(8*x)/(x^2+1) is Maximum(-1,4),Minimum(1,-4)