What is the extreme f(x)= 1/(x-2),0<= x<= 1 ?

The extreme f(x)= 1/(x-2),0<= x<= 1 is Maximum(0,-1/2),Minimum(1,-1)

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extreme f(x)= 1/(x-2),0<= x<= 1

extreme

Maximum (0, - \frac{1}{2}), Minimum (1, - 1)

Solution steps

Find the critical points:

x = 0, x = 1

Domain of

\frac{1}{x - 2}, 0 \leq x \leq 1 : 0 \leq x \leq 1

Find intervals:

Decreasing

: 0 < x < 1

Plug the extreme point

x = 0

into

\frac{1}{x - 2} \Rightarrow y = - \frac{1}{2}

Maximum (0, - \frac{1}{2})

Plug the extreme point

x = 1

into

\frac{1}{x - 2} \Rightarrow y = - 1

Minimum (1, - 1)

Maximum (0, - \frac{1}{2}), Minimum (1, - 1)

What is the extreme f(x)= 1/(x-2),0<= x<= 1 ?
The extreme f(x)= 1/(x-2),0<= x<= 1 is Maximum(0,-1/2),Minimum(1,-1)