extreme f(x)=7ln(3xe^{-x})

Lösung

extrempunkte

f (x) = 7 ln (3 x e^{- x})

Maximum (1, 7 (ln (3) - 1))

Schritte zur Lösung

f^{'} (x) = 7 (\frac{1}{x} - 1)

Intervalle finden:

Ansteigend

: 0 < x < 1,

Absteigend

: 1 < x < \infty

Stecke

x = 1

7 ln (3 x e^{- x}) : 7 (ln (3) - 1)

Maximum (1, 7 (ln (3) - 1))

e x t re m e f (x) = 3 x, - 1 \leq x \leq 1

e x t re m e f (x) = \frac{1}{5} x^{3} - x^{2} + 1

e x t re m e \frac{4 x}{x ^{2} - 1}

e x t re m e 9 - x^{2}

e x t re m e f (x) = 3 x^{3} + 3 x^{2}