extreme (x-1)(x+9)^2

Lösung

extrempunkte

(x - 1) (x + 9)^{2}

Maximum (- 9, 0), Minimum (- \frac{7}{3}, - \frac{4000}{27})

Schritte zur Lösung

f^{'} (x) = (x + 9) (3 x + 7)

Intervalle finden:

Ansteigend

: - \infty < x < - 9,

Absteigend

: - 9 < x < - \frac{7}{3},

Ansteigend

: - \frac{7}{3} < x < \infty

Stecke

x = - 9

(x - 1) (x + 9)^{2} : 0

Maximum (- 9, 0)

Stecke

x = - \frac{7}{3}

(x - 1) (x + 9)^{2} : - \frac{4000}{27}

Minimum (- \frac{7}{3}, - \frac{4000}{27})

Maximum (- 9, 0), Minimum (- \frac{7}{3}, - \frac{4000}{27})

e x t re m e x^{\frac{1}{5}} (x^{2} - 4)

e x t re m e f (x) = cos (\frac{4 x}{3})

e x t re m e \frac{5 x}{1 - x}

e x t re m e K (r, s) = 3 r - 7 s

e x t re m e f (x, y) = - y^{2} + y^{2} x - x^{2} + x