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Popular Functions >

extreme ln(x^2+8)

Solution

extreme

Solution

Minimum (0, 3 ln (2))

Solution steps

f^{'} (x) = \frac{2 x}{x ^{2} + 8}

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

ln (x^{2} + 8) : 3 ln (2)

Minimum (0, 3 ln (2))

Graph

Popular Examples

extreme f(x,y)=(-3x^2-4y^2-9x+5y+3)

extreme y=x^2e^x

extreme f(y)=6x^2+7y^2

extreme f(x)=(t^2)/(1+t^3)

extreme-x^3+6x^2+x-1

Frequently Asked Questions (FAQ)

What is the extreme ln(x^2+8) ?
The extreme ln(x^2+8) is Minimum(0,3ln(2))