What is the extreme f(x,y)=(-3x^2-4y^2-9x+5y+3) ?

The extreme f(x,y)=(-3x^2-4y^2-9x+5y+3) is Maximum(-3/2 , 5/8)

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extreme f(x,y)=(-3x^2-4y^2-9x+5y+3)

extreme

Maximum (- \frac{3}{2}, \frac{5}{8})

Solution steps

Find the critical points:

(- \frac{3}{2}, \frac{5}{8})

\frac{\partial ^{2} f}{\partial x ^{2}} = - 8

D (x, y) = 48

Check the sign of at each critical point

Check critical point

(- \frac{3}{2}, \frac{5}{8}) :

Maximum

Maximum (- \frac{3}{2}, \frac{5}{8})

What is the extreme f(x,y)=(-3x^2-4y^2-9x+5y+3) ?
The extreme f(x,y)=(-3x^2-4y^2-9x+5y+3) is Maximum(-3/2 , 5/8)