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Popular Functions >

extreme f(x)=x^2+3x-7

Solution

extreme

Solution

Minimum (- \frac{3}{2}, - \frac{37}{4})

Solution steps

f^{'} (x) = 2 x + 3

Find intervals:

Decreasing

: - \infty < x < - \frac{3}{2},

Increasing

: - \frac{3}{2} < x < \infty

Plug

x = - \frac{3}{2}

into

x^{2} + 3 x - 7 : - \frac{37}{4}

Minimum (- \frac{3}{2}, - \frac{37}{4})

Graph

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Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2+3x-7 ?
The extreme f(x)=x^2+3x-7 is Minimum(-3/2 ,-37/4)