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Popular Functions >

extreme f(x)=8-5x+x^2

Solution

extreme

Solution

Minimum (\frac{5}{2}, \frac{7}{4})

Solution steps

f^{'} (x) = 2 x - 5

Find intervals:

Decreasing

: - \infty < x < \frac{5}{2},

Increasing

: \frac{5}{2} < x < \infty

Plug

x = \frac{5}{2}

into

8 - 5 x + x^{2} : \frac{7}{4}

Minimum (\frac{5}{2}, \frac{7}{4})

Graph

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extreme f(x)=(5x)/(x^2+16),0<= x<= 12

Frequently Asked Questions (FAQ)

What is the extreme f(x)=8-5x+x^2 ?
The extreme f(x)=8-5x+x^2 is Minimum(5/2 , 7/4)