What is the extreme f(x)=x^4-4x^2-2 ?

The extreme f(x)=x^4-4x^2-2 is Minimum(-sqrt(2),-6),Maximum(0,-2),Minimum(sqrt(2),-6)

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extreme f(x)=x^4-4x^2-2

extreme

Minimum (- 2, - 6), Maximum (0, - 2), Minimum (2, - 6)

Solution steps

f^{'} (x) = 4 x^{3} - 8 x

Find intervals:

Decreasing

: - \infty < x < - 2,

Increasing

: - 2 < x < 0,

Decreasing

: 0 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = - 2

into

x^{4} - 4 x^{2} - 2 : - 6

Minimum (- 2, - 6)

Plug

x = 0

into

x^{4} - 4 x^{2} - 2 : - 2

Maximum (0, - 2)

Plug

x = 2

into

x^{4} - 4 x^{2} - 2 : - 6

Minimum (2, - 6)

Minimum (- 2, - 6), Maximum (0, - 2), Minimum (2, - 6)

What is the extreme f(x)=x^4-4x^2-2 ?
The extreme f(x)=x^4-4x^2-2 is Minimum(-sqrt(2),-6),Maximum(0,-2),Minimum(sqrt(2),-6)