What is the extreme f(x)=2x^3+3x^2-72x+4 ?

The extreme f(x)=2x^3+3x^2-72x+4 is Maximum(-4,212),Minimum(3,-131)

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extreme f(x)=2x^3+3x^2-72x+4

extreme

Maximum (- 4, 212), Minimum (3, - 131)

Solution steps

f^{'} (x) = 6 x^{2} + 6 x - 72

Find intervals:

Increasing

: - \infty < x < - 4,

Decreasing

: - 4 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = - 4

into

2 x^{3} + 3 x^{2} - 72 x + 4 : 212

Maximum (- 4, 212)

Plug

x = 3

into

2 x^{3} + 3 x^{2} - 72 x + 4 : - 131

Minimum (3, - 131)

Maximum (- 4, 212), Minimum (3, - 131)

What is the extreme f(x)=2x^3+3x^2-72x+4 ?
The extreme f(x)=2x^3+3x^2-72x+4 is Maximum(-4,212),Minimum(3,-131)