What is the extreme f(x)=7x^2-28x+3,-5<= x<= 4 ?

The extreme f(x)=7x^2-28x+3,-5<= x<= 4 is Maximum(-5,318),Minimum(2,-25),Maximum(4,3)

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extreme f(x)=7x^2-28x+3,-5<= x<= 4

extreme

Maximum (- 5, 318), Minimum (2, - 25), Maximum (4, 3)

Solution steps

Find the critical points:

x = - 5, x = 2, x = 4

Domain of

7 x^{2} - 28 x + 3, - 5 \leq x \leq 4 : - 5 \leq x \leq 4

Find intervals:

Decreasing

: - 5 < x < 2,

Increasing

: 2 < x < 4

Plug the extreme point

x = - 5

into

7 x^{2} - 28 x + 3 \Rightarrow y = 318

Maximum (- 5, 318)

Plug the extreme point

x = 2

into

7 x^{2} - 28 x + 3 \Rightarrow y = - 25

Minimum (2, - 25)

Plug the extreme point

x = 4

into

7 x^{2} - 28 x + 3 \Rightarrow y = 3

Maximum (4, 3)

Maximum (- 5, 318), Minimum (2, - 25), Maximum (4, 3)

What is the extreme f(x)=7x^2-28x+3,-5<= x<= 4 ?
The extreme f(x)=7x^2-28x+3,-5<= x<= 4 is Maximum(-5,318),Minimum(2,-25),Maximum(4,3)