What is the extreme f(x)=5+54x+2x^3,0<= x<= 4 ?

The extreme f(x)=5+54x+2x^3,0<= x<= 4 is Minimum(0,5),Maximum(4,349)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

extreme f(x)=5+54x+2x^3,0<= x<= 4

extreme

Minimum (0, 5), Maximum (4, 349)

Solution steps

Find the critical points:

x = 0, x = 4

Domain of

5 + 54 x + 2 x^{3}, 0 \leq x \leq 4 : 0 \leq x \leq 4

Find intervals:

Increasing

: 0 < x < 4

Plug the extreme point

x = 0

into

5 + 54 x + 2 x^{3} \Rightarrow y = 5

Minimum (0, 5)

Plug the extreme point

x = 4

into

5 + 54 x + 2 x^{3} \Rightarrow y = 349

Maximum (4, 349)

Minimum (0, 5), Maximum (4, 349)

What is the extreme f(x)=5+54x+2x^3,0<= x<= 4 ?
The extreme f(x)=5+54x+2x^3,0<= x<= 4 is Minimum(0,5),Maximum(4,349)