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Popular Functions >

extreme-0.25x^2+40x+300

Solution

extreme

Solution

Maximum (80, 1900)

Solution steps

f^{'} (x) = - 0.5 x + 40

Find intervals:

Increasing

: - \infty < x < 80,

Decreasing

: 80 < x < \infty

Plug

x = 80

into

- 0.25 x^{2} + 40 x + 300 : 1900

Maximum (80, 1900)

Graph

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Frequently Asked Questions (FAQ)

What is the extreme-0.25x^2+40x+300 ?
The extreme-0.25x^2+40x+300 is Maximum(80,1900)