What is the derivative of 8x^4-24x^2+r-1 ?

The derivative of 8x^4-24x^2+r-1 is 32x^3-48x+(dr)/(dx)

What is the first derivative of 8x^4-24x^2+r-1 ?

The first derivative of 8x^4-24x^2+r-1 is 32x^3-48x+(dr)/(dx)

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\frac{d}{d x} (8 x^{4} - 24 x^{2} + r - 1)

32 x^{3} - 48 x + \frac{d r}{d x}

Solution steps

\frac{d}{d x} (8 x^{4} - 24 x^{2} + r - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (8 x^{4}) - \frac{d}{d x} (24 x^{2}) + \frac{d r}{d x} - \frac{d}{d x} (1)

\frac{d}{d x} (8 x^{4}) = 32 x^{3}

\frac{d}{d x} (24 x^{2}) = 48 x

\frac{d}{d x} (1) = 0

= 32 x^{3} - 48 x + \frac{d r}{d x} - 0

Simplify

= 32 x^{3} - 48 x + \frac{d r}{d x}

What is the derivative of 8x^4-24x^2+r-1 ?
The derivative of 8x^4-24x^2+r-1 is 32x^3-48x+(dr)/(dx)
What is the first derivative of 8x^4-24x^2+r-1 ?
The first derivative of 8x^4-24x^2+r-1 is 32x^3-48x+(dr)/(dx)