What is the shift f(x)=cos(2x-pi/2) ?

The shift f(x)=cos(2x-pi/2) is Phase: pi/4 , Vertical:0

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shift f(x)=cos(2x-pi/2)

shift

f (x) = cos (2 x - \frac{π}{2})

Phase : \frac{π}{4}, Vertical : 0

Solution steps

f (x) = cos (2 x - \frac{π}{2})

g (B x - C) = cos (2 x - \frac{π}{2}), B = 2, C = \frac{π}{2}, D = 0

Therefore, the phase shift

\frac{C}{B}

\frac{\frac{π}{2}}{2}

\frac{π}{4}

The vertical shift

D

0

0

f (x) = 2 - 3 x^{2}

f (x) = \frac{10 x - 18}{x ^{2} - 7 x + 10}

(1, 3), (- 1, - 1)

y = - x^{2} - 10 x + 56

f (x) = x^{3} + \frac{3}{2} x^{2} - 6 x + 10

What is the shift f(x)=cos(2x-pi/2) ?
The shift f(x)=cos(2x-pi/2) is Phase: pi/4 , Vertical:0